6x^(2)+16x+10=0

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Solution for 6x^(2)+16x+10=0 equation: 



6x^(2)+16x+10=0

a = 6; b = 16; c = +10;
Δ = b2-4ac
Δ = 162-4·6·10
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4}{2*6}=\frac{-20}{12}
=-1+2/3
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4}{2*6}=\frac{-12}{12}
=-1
$

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